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PE Power reference

Core circuits and the formulas you'll reach for most on the PE Power exam.

Circuit diagrams

RL
Series R–L circuit (AC source)
abcn
Three-phase wye (Y) connection
VinR1VoutR2
Resistive voltage divider
Load
One-line: source · transformer · bus · load

Formula sheet

Three-phase power
Real powerP=3VLLILcosθP = \sqrt{3}\,V_{LL} I_L \cos\theta
Reactive powerQ=3VLLILsinθQ = \sqrt{3}\,V_{LL} I_L \sin\theta
Apparent powerS=3VLLIL=P2+Q2S = \sqrt{3}\,V_{LL} I_L = \sqrt{P^2 + Q^2}
Power factorpf=cosθ=PSpf = \cos\theta = \dfrac{P}{S}
Per-unit system
Base currentIbase=Sbase3VLL,baseI_{base} = \dfrac{S_{base}}{\sqrt{3}\,V_{LL,base}}
Base impedanceZbase=VLL,base2SbaseZ_{base} = \dfrac{V_{LL,base}^2}{S_{base}}
Change of baseZpunew=Zpuold(VoldVnew)2SnewSoldZ_{pu}^{new} = Z_{pu}^{old}\left(\dfrac{V_{old}}{V_{new}}\right)^2\dfrac{S_{new}}{S_{old}}
Rotating machines
Synchronous speedns=120fPn_s = \dfrac{120 f}{P}
Slips=nsnrnss = \dfrac{n_s - n_r}{n_s}
Rotor frequencyfr=sff_r = s\,f
Transmission & faults
Approx. voltage dropVdropI(Rcosθ+Xsinθ)V_{drop} \approx I\,(R\cos\theta + X\sin\theta)
Surge impedance loadingSIL=VLL2ZcSIL = \dfrac{V_{LL}^2}{Z_c}
Per-unit fault currentIf=VpuXpuI_f = \dfrac{V_{pu}}{X_{pu}}
Power electronics
Full-wave avg. outputVdc=2VmπV_{dc} = \dfrac{2 V_m}{\pi}
Half-wave avg. outputVdc=VmπV_{dc} = \dfrac{V_m}{\pi}
RMS of sinusoidVrms=Vm2V_{rms} = \dfrac{V_m}{\sqrt{2}}